-5w^2-3w+2=0

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Solution for -5w^2-3w+2=0 equation:



-5w^2-3w+2=0
a = -5; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·(-5)·2
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-7}{2*-5}=\frac{-4}{-10} =2/5 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+7}{2*-5}=\frac{10}{-10} =-1 $

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